#Python Function to determine whether the year is a leap year or not.Any year is entered through the keyboard.
def find(a):
if(((a % 4) and (a % 100) and (a % 400))==0):
i=1
else:
i=0
return i
print("\nEnter an year : ")
year = int(input())
leap=find(year)
if(leap==1):
print("\n", year ," year is leap year ")
else:
print("\n", year ," year is not a leap year ")